How can I replace a integer that shows up twice in a random list

Question

I have a list that looks like this:

l = [random.randint(0,9),random.randint(0,9),random.randint(0,9),random.randint(0,9)]

but if it outputs something like this[9,0,5,5] what can I do replace the repeating integer?

Also related [generate 3 different random numbers](https://stackoverflow.com/questions/22577916/generate-3-different-random-numbers). — ShadowRanger, Dec 04 '15 at 03:43

score 2 · Accepted Answer · answered Dec 04 '15 at 03:26

2

If the goal is to get four unique items in random order, let Python do the work for you:

l = random.sample(range(10), 4)

random.sample is intended specifically for "random sampling without replacement", which appears to be the goal of your code.

answered Dec 04 '15 at 03:26

ShadowRanger

I do need the numbers in a list is this possible – Safe G Dec 04 '15 at 03:36
@SafeG: `random.sample` returns a `list` already. Example from my local computer: `>>> random.sample(range(10), 4)` output: `[0, 5, 7, 6]`. – ShadowRanger Dec 04 '15 at 03:38
THANK YOU!!!! I have been looking for days at this! – Safe G Dec 04 '15 at 03:42

1 Answers1