Simple if else shell script

Asked Dec 02 '15 at 13:10

Active Dec 02 '15 at 13:24

Viewed 166 times

I try to execute the file sample.sh using the command sh sample.sh, which contains the below code:

#!/bin/sh

a=10
b=20

if [ $a == $b ]
then
   echo "a is equal to b"
else
   echo "a is not equal to b"
fi

So when I try to execute I get the below error:

: command not foundine 2:
: command not foundine 5:
sample.sh: line 11: syntax error near unexpected token `fi'
sample.sh: line 11: `fi'

Can someone help me out, where am I going wrong please?

edited Dec 02 '15 at 13:15

Biffen

asked Dec 02 '15 at 13:10

Mani Kandan

What line endings does the file have? – Biffen Dec 02 '15 at 13:15
am very new to shell program Biffen, so can u share what line endings means – Mani Kandan Dec 02 '15 at 13:17
See https://en.wikipedia.org/wiki/Newline For a quick fix, run `dos2unix sample.sh`. – Biffen Dec 02 '15 at 13:18
Or does it work if you use `=` instead of `==`? – Biffen Dec 02 '15 at 13:23
if i rin dos2unix sample.sh i get below error. -bash: dos2unix: command not found – Mani Kandan Dec 02 '15 at 13:23
Then you don't have `dos2unix` (surely you could understand that?). – Biffen Dec 02 '15 at 13:24
ya i can,should i instal that in my server – Mani Kandan Dec 02 '15 at 13:25

0 Answers0