14

I am having string like

"11-04-2015 22:01:13:053" or "32476347656435"

How can I check if string is Date?
Checking String if it is numeric using regex

String regex = "[0-9]+";
Tushar
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Neeti
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5 Answers5

27

Other person are also correct

This is your answer

import java.text.ParseException;
import java.text.SimpleDateFormat;

public class date {
    public static boolean isValidDate(String inDate) {
        SimpleDateFormat dateFormat = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss:ms");
        dateFormat.setLenient(false);
        try {
            dateFormat.parse(inDate.trim());
        } catch (ParseException pe) {
            return false;
        }
        return true;
    }

    public static void main(String[] args) {

        System.out.println(isValidDate("20-01-2014"));
        System.out.println(isValidDate("11-04-2015 22:01:33:023"));

        System.out.println(isValidDate("32476347656435"));
    }
}
Mariano
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amit prasad
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3

java.time

It’s about time someone provides the modern answer. The SimpleDateFormat class mentioned in a couple of the other answers is notoriously troublesome and fortunately now long outdated. Instead the modern solution uses java.time, the modern Java date and time API.

    DateTimeFormatter formatter = DateTimeFormatter.ofPattern("dd-MM-uuuu HH:mm:ss:SSS");

    String stringToTest = "11-04-2015 22:01:13:053";

    try {
        LocalDateTime dateTime = LocalDateTime.parse(stringToTest, formatter);
        System.out.println("The string is a date and time: " + dateTime);
    } catch (DateTimeParseException dtpe) {
        System.out.println("The string is not a date and time: " + dtpe.getMessage());
    }

Output from this snippet is:

The string is a date and time: 2015-04-11T22:01:13.053

Suppose that instead the string was defined as:

    String stringToTest = "32476347656435";

Now the output is:

The string is not a date and time: Text '32476347656435' could not be parsed at index 2

Link: Oracle tutorial: Date Time explaining how to use java.time.

Ole V.V.
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1

There are two possible solutions:

Davide Lorenzo MARINO
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0

The best solution is to actually try to parse it to a date with DateTime.TryParse().

String d = "11-04-2015 22:01:13:053";

DateTime dt = new DateTime();

if (DateTime.TryParse(d, out dt)) { 
    /// yes, it's a date, do something here... 
} else {
    // no, it's not a date, do something else here... 
}
Matt Ke
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Sean Munson
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  • This solution is only useful to check if a string with a specific format can be interpretted as a valid date. Dates can be written in so many ways, so a more intelligent match routine is probably what is called for. Further more, some strings that represent dates could have multiple interpretations, for example "03/03/08". Is it March 3rd 2008 - or is it 8th of March 2003? – Mads Boyd-Madsen Jan 30 '19 at 22:31
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    I believe that `DateTime.TryParse` is a .NET function not accessible from Java. And I believe a Java solution was asked for. – Ole V.V. Nov 07 '19 at 19:07
0

You can use Apache Commons Validator. It provides validation framework for validating date, time, numbers, currency, IP address, email, and URL.

Maven dependency:

<dependency>
    <groupId>commons-validator</groupId>
    <artifactId>commons-validator</artifactId>
    <version>1.6</version>
</dependency>

Example:

assertTrue(GenericValidator.isDate("2019-02-28", "yyyy-MM-dd", true))
Matt Ke
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Siva Saindra Reddy K
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