Get url link from the web using python

Question

So I am trying to write a script that will allow to search for a certain place and get the coordinates. I am very limited with the packages because I'm not allow download any packages that does not already comes with python 2.7.

import webbrowser

location = input('Enter your location: ')

webbrowser.open('https://www.google.com/maps/place/'+location)

My browser opens and the url changes to

https://www.google.com/maps/place/Washington+Monument/@38.8894838,-77.0374678,17z/data=!3m1!4b1!4m2!3m1!1s0x89b7b7a1be0c2e7f:0xe97346828ed0bfb8

From there, I want to get the new url so I can strip it to just have the coordinates. Anyone one know how to get the new url the browser creates?

If the user is entering the location information, why not just strip the coordinates from there? Why bother with a browser at all? — John Gordon, Nov 02 '15 at 21:06

score 1 · Answer 1 · answered Nov 02 '15 at 21:16

1

>>> import urllib
>>> text = urllib.urlopen('https://www.google.com/maps/place/washington').read()
>>> p = text.find('cacheResponse([[[')
>>> p
228
>>> text[228: 300]
'cacheResponse([[[26081602.52827102,-95.67706800000001,37.06250000000001]'
>>>

answered Nov 02 '15 at 21:16

xrisk

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score 0 · Answer 2 · answered Nov 02 '15 at 21:23

0

You could use Selenium's Python library:

>>> from selenium import webdriver
>>> driver = webdriver.Firefox()
>>> driver.get('https://www.google.com/maps/place/Washington')
>>> driver.current_url
https://www.google.com/maps/place/Washington,+DC/@38.8992651,-77.1546507,11z/data=!3m1!4b1!4m2!3m1!1s0x89b7c6de5af6e45b:0xc2524522d4885d2a

answered Nov 02 '15 at 21:23

Celeo

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OP says he is not allowed to install any packages. However good approach nonetheless – Wondercricket Nov 02 '15 at 21:24

Get url link from the web using python

2 Answers2