excluding an internal element while slicing

Question

So I've got a list...

a = [1,2,3,4,5]

I can produce b without 5 by saying:

b = a[:-1]

How do I produce c without 3?

c = a[:2:]?

Answer 1

By adding two lists

>>> a = [1,2,3,4,5]
>>> c = a[:3-1] + a[3:]   # Explicitly mentioned 3-1 to help understand better
>>> c
[1, 2, 4, 5]

An inplace way to remove

>>> a = [1,2,3,4,5]
>>> a.pop(3-1)
3
>>> a
[1, 2, 4, 5]

Answer 2

One method is to join the two list parts together as follows

a = [1,2,3,4,5]
c = a[:2] + a[3:]
c
[1,2,4,5]

Answer 3

You would need to slice twice and concatenate the lists , Example -

c = a[:2] + a[3:]  #2 being the index of element `3` in the array.

Demo -

>>> a = [1,2,3,4,5]
>>> a[:2] + a[3:]
[1, 2, 4, 5]

Answer 4

You can also just pop the index out i.e.

>>> a = [1,2,3,4,5]
>>> a.pop(2)
>>> 3
>>> print(a)
[1,2,4,5]