Why is this forloop running if the if statement is false?

Question

My for loop is still being executed even if my if statement is false. For example I type something random instead of straight line and the forloop will still run and output the cost. Why is that?

if (method.equalsIgnoreCase("applesauce"));
{
    for (i = 0; i <span; i++) 
    {
        total = total * apple;
        additional++;
        System.out.println(total);

    }
}

Sorry sotirios, I didn't know the semicolon terminated the if statement. I didn't search for that beforehand because I wasn't aware of it. — HelpMe, Oct 02 '15 at 03:32

score 2 · Answer 1 · edited Oct 02 '15 at 04:14

2

if (method.equalsIgnoreCase("applesauce"));  <--

You terminated your statement right away with an ; When you write ; at the end of statement it terminates right there.

Your current code can be translated as

if (method.equalsIgnoreCase("applesauce")) {

}

{
    for (i = 0; i <span; i++) 
    {
        total = total * apple;
        additional++;
        System.out.println(total);
    }
}

edited Oct 02 '15 at 04:14

user253751

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answered Oct 02 '15 at 03:30

Suresh Atta

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Thank you! Been looking at it for awhile – HelpMe Oct 02 '15 at 03:31

Why is this forloop running if the if statement is false?

1 Answers1