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Is it possible to open Safari app settings using NSURL link ?

Here is the code i'm using for general settings

UIApplication.sharedApplication().openURL(NSURL(string: UIApplicationOpenSettingsURLString)!)

How should i modify it - if its even possible?

Thank you!

David Robertson
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1 Answers1

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I have found this post: Call the official *Settings* app from my app on iPhone

From that post follow this two steps:

First go to Info -> URL Types and add URL Schemes as prefs as shown in below image:

enter image description here

After that use this code for open safari settings:

UIApplication.sharedApplication().openURL(NSURL(string: "prefs:root=Safari")!)

And result will be:

enter image description here

Community
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Dharmesh Kheni
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