how to skip the index in python for loop

Question

I have a list like this:

array=['for','loop','in','python']

for arr in array:
    print arr

This will give me the output

for
lop
in
python

I want to print

in
python

How can I skip the first 2 indices in python?

Answer 1

Use slicing.

array = ['for','loop','in','python']

for arr in array[2:]:
    print arr

When you do this, the starting index in the for loop becomes 2. Thus the output would be:

in
python

For more info on slicing read this: Explain Python's slice notation

Answer 2

Code:

array=['for','loop','in','python']
for arr in array[2:]:
    print arr

Output:

in
python

Answer 3

See Python slicing:

for arr in array[2:]:
    print arr

Answer 4

If you want to skip other lines or want to try different combination then you could do this

Code:

for i ,j in enumerate(array):
    if i not in (1,2):
        print j

Output:

for
python

Answer 5

Slicing is good, but if you're considered about performance, you might prefer itertools.islice:

import itertools
array = 'for loop in python'.split()
for x in itertools.islice(array, 2, None):
    print x

because the slice operator builds a completely new list, which means overhead if you just want to iterate over it.