How do I get the size of an int*?

Question

I want to get the size of an integer array in C++. If a method takes in an int* how do I get the size of that value?

int myMethod(int* values)
{
     values.size();

}

this give compilation errors

Do you mean you've passed in an array, and want to find its length ? — nos, Aug 23 '15 at 14:07
You cannot, size needs to be passed as parameter. Better use `std::vector `. — πάντα ῥεῖ, Aug 23 '15 at 14:09

Basile Starynkevitch · Accepted Answer · 2015-08-23T14:21:01.950

You could get the size of of a pointer to an integer with sizeof(int*).

However, given a pointer value, there is no portable way (in C or C++) to get the dynamic -runtime- size of the pointed memory zone (in heap or elsewhere).

A general advice is to avoid raw pointers when possible: use smart pointers (from <memory> header) and standard C++ containers (e.g. std::vector from <vector>)

So if you declared std::vector<int> values; you could get the vector size with values.size();

How do I get the size of an int*?

1 Answers1