I am wondering if JavaScript supports writing a function within another function, or nested functions (I read it in a blog). Is this really possible?. In fact, I have used these but am unsure of this concept. I am really unclear on this -- please help!
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224
Is this really possible.
Yes.
function a(x) { // <-- function
function b(y) { // <-- inner function
return x + y; // <-- use variables from outer scope
}
return b; // <-- you can even return a function.
}
console.log(a(3)(4));
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35This method is called currying. – Yekver Nov 29 '14 at 21:45
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function a(x) { // – Anne Ortiz Jul 20 '20 at 19:42
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so are functions a type of object? sorry for necro – CiY3 Feb 15 '22 at 00:07
32
The following is nasty, but serves to demonstrate how you can treat functions like any other kind of object.
var foo = function () { alert('default function'); }
function pickAFunction(a_or_b) {
var funcs = {
a: function () {
alert('a');
},
b: function () {
alert('b');
}
};
foo = funcs[a_or_b];
}
foo();
pickAFunction('a');
foo();
pickAFunction('b');
foo();
Quentin
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4Great example. I would add that it's important to note that functions defined inside other functions only exist in that functions scope (unless, of course, you assign a global function to it, as per this example). – Mike Sherov Jul 09 '10 at 12:27
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5
21
Functions are first class objects that can be:
- Defined within your function
- Created just like any other variable or object at any point in your function
- Returned from your function (which may seem obvious after the two above, but still)
To build on the example given by Kenny:
function a(x) {
var w = function b(y) {
return x + y;
}
return w;
};
var returnedFunction = a(3);
alert(returnedFunction(2));
Would alert you with 5.
cgp
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15
Yes, it is possible to write and call a function nested in another function.
Try this:
function A(){
B(); //call should be B();
function B(){
}
}
cнŝdk
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user3261767
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12
Not only can you return a function which you have passed into another function as a variable, you can also use it for calculation inside but defining it outside. See this example:
function calculate(a,b,fn) {
var c = a * 3 + b + fn(a,b);
return c;
}
function sum(a,b) {
return a+b;
}
function product(a,b) {
return a*b;
}
document.write(calculate (10,20,sum)); //80
document.write(calculate (10,20,product)); //250
Stefan Gruenwald
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3
An alternative solution with ES6 to other answers:
const currying = (x) => (y)=> x + y;
console.log(currying(5)(3));
will print to console: 8
Sedat Polat
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1A great read on this and a reason as to why it is called 'currying' can be found here https://javascript.info/currying-partials#currying-what-for – Andre Dec 13 '21 at 18:25
0
function calculate(num1) {
// arrow function
return (num2) => num1 + num2;
}
// Invoke the function
console.log(calculate(4)(6));