Allow literal . in regular expression

Question

^[a-zA-Z]:{1}/(\w+/)+$

I want to allow . as well in the expression in \w+. How can I do this?

`{1}` is completely redundant, by the way, `:{1}` makes **:** match only once, which is the same as `:`. — Kobi, Jul 08 '10 at 09:06
To add to Kobi's excellent point: http://stackoverflow.com/questions/3032593/using-explicitly-numbered-repetition-instead-of-question-mark-star-and-plus — polygenelubricants, Jul 09 '10 at 10:58

score 9 · Accepted Answer · answered Jul 07 '10 at 17:15

9

\. should do it. You don't need the escaping \ if you put it in a character class. For your exact example:

^[a-zA-Z]:{1}/([\w.]+/)+$

answered Jul 07 '10 at 17:15

Carl Norum

score 3 · Answer 2 · answered Jul 07 '10 at 17:17

3

The . is a special character in regular expression syntax, so you have to escape it with a backslash. \.

answered Jul 07 '10 at 17:17

Bill the Lizard

score 1 · Answer 3 · answered Jul 07 '10 at 17:18

1

Replace

(\w+/)

with

([\w.]+/)

answered Jul 07 '10 at 17:18

strager

serhio · Answer 4 · 2010-07-15T17:11:00.043

0

The expression should be ^[a-zA-Z]:/(\w+./)+$ or ^[a-zA-Z]:/([\w.]+/)+$

edited Jul 15 '10 at 17:11

answered Jul 07 '10 at 17:30

serhio

Um, no? Now you're matching one alnum character `\w` and any character `.` where the OP wants one or more alnums or dots, followed by a slash, repeated once or more. – Tim Pietzcker Jul 15 '10 at 17:07
I didn't downvote, but as I wrote above, your answer is plain wrong. – Tim Pietzcker Jul 15 '10 at 17:08
understood. thanks! I thought for a moment that \w is for a word – serhio Jul 15 '10 at 17:11

4 Answers4