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I want to do multivariable assignment. I can do [a,b] = min([1 2 3]) but I can't do [a,b] = [1,2]. Why? Is there any workaround?

piotrek
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  • Examples in this PAQ http://stackoverflow.com/questions/9908398/octave-basics-how-to-assign-variables-from-a-vector – Cobusve Aug 08 '15 at 14:22
  • Please consider removing the Matlab tag since the accepted answer won't work there. My answer using `deal` would do the job in Octave and Matlab. – Matt Aug 08 '15 at 14:30

3 Answers3

2

The [1,2] on the right hand side of the assignment is interpreted as array with the two elements 1 and 2.

If you want to do the multi-variable-assignment in one line, you can use deal in Matlab. This should work in Octave as well according to the documentation here.

>> [a,b] = deal(1,2)
a =
     1
b =
     2

The advantage of using deal is that it works in Matlab as well, where the solution with [a b] = {1 2}{:} won't.

Matt
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2

Octave basics: How to assign variables from a vector

>> [a b c] = {5 6 7}{:}
a =  5
b =  6
c =  7
Community
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Cobusve
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0

To adapt Cobusve's answer to Matlab, two lines are required:

>> h={5 6 7}

h = 

    [5]    [6]    [7]

>> [a b c]=h{:}

a =

     5


b =

     6


c =

     7
Daniel
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