Split or Extract Strings into Arguments of Function?

Question

Lets say I have a function that takes string arguments. But I want to dynamically generate them. There does not seem to be a way to plug this in easily. How is this done? See my example here

i_take_strings('one', 'two', 'and_the_letter_C')

s = 'one two and_the_letter_c'

i_take_strings(x for x in s.split()) #python thinks I'm retarded with this attempt

i_take_string(*tuple([x for x in s.split()])) would do, what you do is creating a generator, not a list. — mission.liao, Aug 03 '15 at 04:42
@mission.liao code would work but could be simplified to `i_take_strings(*s.split())`. See [Pass list to function](https://stackoverflow.com/questions/3961007/passing-an-array-list-into-python) for more — LinkBerest, Aug 03 '15 at 04:46
Python should not think you're retarded. You just tell it to pass an generator to the function - and python will do just that without questioning your mental health. — skyking, Aug 03 '15 at 05:47

score 7 · Accepted Answer · edited May 23 '17 at 12:23

7

s.split() already returns a list so you can pass it to your function as variable arguments by prepending * like follows:

i_take_strings(*s.split())

edited May 23 '17 at 12:23

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answered Aug 03 '15 at 04:44

Ozgur Vatansever

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Very nice. Today I learned something new in Python. Rejoice with me. – 1Up Aug 03 '15 at 04:46

Split or Extract Strings into Arguments of Function?

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