Test for / character in between all pairs of opening and closing double quotes

Question

I'm trying to test if the / character is inside double quotes within a JavaScript string. For instance, "hello/world" will match, whereas hello/world/"How are you" will fail because it's outside of the double quotes. I've been looking around and haven't found an answer to this.

Also, "hello"world/how"are you" should fail as the opening and closing double quotes do not encapsulate the /, as determined from left to right. To reiterate, I want to match all instances within/inside/in between closing and opening double quotes, which is unlike Alternative to regex: match all instances not inside quotes

@Barmar great question. That should pass as the opening and closing double quotes are not encapsulating the `/`, as determined from left to right — FullStack, Jul 26 '15 at 06:42
You should clarify that in the question, since several of the answers get it wrong. — Barmar, Jul 26 '15 at 06:44
I think there's confusion about "matching", "failing" and "passing". I have edited my question to be more clear. — FullStack, Jul 26 '15 at 06:55

shA.t · Accepted Answer · 2015-07-26T06:41:30.997

2

I think you can use this:

/^(((\"[^"\/]*\")\/?)|([^"\/]*\/?))+$/igm

or

/^(\"[^"\/]*\"|[^"\/]*\/?)+$/im

[Regex Demo]

edited Jul 26 '15 at 06:41

answered Jul 26 '15 at 06:35

shA.t

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You can simplify it to `/^("[^"\/]*"\/?|[^"\/]*\/?)+$/igm`. – Gumbo Jul 26 '15 at 06:39
@Gumbo I wax simplifying it and the best I found is now added ;). – shA.t Jul 26 '15 at 06:42
this works the best so far out of all answers – FullStack Jul 26 '15 at 08:24

score -1 · Answer 2 · edited Jul 26 '15 at 06:44

-1

str = 'hello/world"how are you"';

q1 = str.indexOf('"');
q2 = str.lastindexof('"');
slsh = str.indexOf("/");
if( slsh > q1 && slsh <q2){

    dosomething;
}

edited Jul 26 '15 at 06:44

shA.t

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answered Jul 26 '15 at 06:38

StillLearningGuy

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Why would you edit that? It was perfectly fine. – StillLearningGuy Jul 26 '15 at 06:46
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If you are not agree you can edit it any time again or roll it back ;). – shA.t Jul 26 '15 at 06:54
Im more upset that I got 2 downvotes with no commemts as to why. – StillLearningGuy Jul 26 '15 at 06:55
Agree @StillLearningGuy downvotes are not motivating us to help share answers lemme upvote yours... – Hace Jul 26 '15 at 07:00
I'd guess the downvotes are because it's not a useful answer. Why? Well, consider the string `"hello"world/how"are you"` - your answer would (incorrectly) indicate that the '/' IS between '"' - much like every other answer except 1 – Jaromanda X Jul 26 '15 at 07:12
I also don't down vote this - but I think you need to use your solution in a loop to check next double-quoted blocks ;). – shA.t Jul 26 '15 at 07:18
It was supposed to be a something to get him started, instead of spoon feexing everyone everything. – StillLearningGuy Jul 26 '15 at 07:22

Hace · Answer 3 · 2015-07-26T06:49:54.083

-1

Without using regex's an algorithm would be something like... Please test yourself!

 Startquotehit = false
    insidequote = false
    Gotaslash = false
    Wantedresult = false

    For x to.. String.length
    {
    If x == quote
    {
     Startquotehit = true;
     Insidequote = !insidequote;
     If gotaslash == true && insidequote
         Wantedresult = true;
    }     

    If x == slash
    {
      If startquotehit
         Gotaslash = true;
    }
 }

Wantedresult would tell you if the slash was quoted 'inside quotes' to cover your false scenario of "....".../..."..."

edited Jul 26 '15 at 06:49

answered Jul 26 '15 at 06:42

Hace

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Why downvote? Yes clumsier than rexexes but it should work :) – Hace Jul 26 '15 at 06:53

score -2 · Answer 4 · edited Jul 26 '15 at 06:52

-2

/".*\/.*"/.test(your_string)

See JavaScript regular expressions' test method.

edited Jul 26 '15 at 06:52

Samuel Liew

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answered Jul 26 '15 at 06:38

Vidul

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This will give the wrong answer for `"quoted begin" not/quoted "quoted end"` – Barmar Jul 26 '15 at 06:40
@Barmar: That's not the example. – Vidul Jul 26 '15 at 06:44
1

Yes, I generalized. And I guessed correctly that this should pass, see his comment. – Barmar Jul 26 '15 at 06:46
@Barmar: Good that you have clarified the requirements :) – Vidul Jul 26 '15 at 06:48
@Jaromanda X: What's your point? A programming task is not about ANY possible input / output, but a concrete one (unless you are emulating Microsoft). – Vidul Jul 26 '15 at 06:59

Test for / character in between all pairs of opening and closing double quotes

4 Answers4