Get loop count inside a for-loop

Question

This for loop iterates over all elements in a list:

for item in my_list:
    print item

Is there a way to know within the loop how many times I've been looping so far? For instance, I want to take a list and after I've processed ten elements I want to do something with them.

The alternatives I thought about would be something like:

count=0
for item in my_list:
    print item
    count +=1
    if count % 10 == 0:
        print 'did ten'

Or:

for count in range(0,len(my_list)):
    print my_list[count]
    if count % 10 == 0:
        print 'did ten'

Is there a better way (just like the for item in my_list) to get the number of iterations so far?

You might also be interested in the answers to iterating over a list in chunks: http://stackoverflow.com/questions/434287/what-is-the-most-pythonic-way-to-iterate-over-a-list-in-chunks — Dave Bacher, Jul 01 '10 at 23:25
possible duplicate of [Accessing the index in Python for loops](http://stackoverflow.com/questions/522563/accessing-the-index-in-python-for-loops) — Ciro Santilli Путлер Капут 六四事, Jul 03 '15 at 14:15

score 729 · Accepted Answer · edited May 08 '22 at 17:52

729

The pythonic way is to use enumerate:

for idx, item in enumerate(my_list):

edited May 08 '22 at 17:52

Mateen Ulhaq

21,459
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answered Jul 01 '10 at 23:02

Nick Bastin

29,060
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Super duper , Just one magic line solving all problems – prashant thakre Dec 20 '21 at 10:24

Vikram Garg · Answer 2 · 2017-10-07T12:21:29.143

114

Agree with Nick. Here is more elaborated code.

#count=0
for idx, item in enumerate(list):
    print item
    #count +=1
    #if count % 10 == 0:
    if (idx+1) % 10 == 0:
        print 'did ten'

I have commented out the count variable in your code.

edited Oct 07 '17 at 12:21

answered Oct 16 '13 at 08:34

Vikram Garg

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You could also use `enumerate`'s optional `start` parameter to start enumerating with 1 instead of 0, though then I'd use the OP's name `count` instead of `idx`. – Stefan Pochmann Oct 07 '17 at 12:36

score 2 · Answer 3 · edited Mar 16 '21 at 20:59

2

Using zip function we can get both element and index.

countries = ['Pakistan','India','China','Russia','USA']

for index, element in zip(range(0,countries),countries):

         print('Index : ',index)
         print(' Element : ', element,'\n')

output : Index : 0 Element : Pakistan ...

See also :

Python.org

edited Mar 16 '21 at 20:59

Hans Ginzel

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answered Mar 14 '20 at 10:33

Muhammad Faizan Fareed

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score 0 · Answer 4 · answered Jan 24 '17 at 22:49

0

I know rather old question but....came across looking other thing so I give my shot:

[each*2 for each in [1,2,3,4,5] if each % 10 == 0])

answered Jan 24 '17 at 22:49

hephestos

464
5
19

score 0 · Answer 5 · answered Nov 22 '21 at 17:17

0

This is something you can also do to check for the list index. When it hits the list index 9, which is the 10th element of the list, it will print "did ten".

for item in list:
    print item
    if list.index(item) == 9:
        print 'did ten'

answered Nov 22 '21 at 17:17

Vatsal Dutt

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This won't work for `list`s with duplicate elements like `[0, 1, 2, 0]` – M. Zhang Nov 23 '21 at 00:00

Get loop count inside a for-loop

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