simple way to drop milliseconds from python datetime.datetime object

Question

My colleague needs me to drop the milliseconds from my python timestamp objects in order to comply with the old POSIX (IEEE Std 1003.1-1988) standard. The tortured route that accomplishes this task for me is as follows:

datetime.datetime.strptime(datetime.datetime.today().strftime("%Y-%m-%d %H:%M:%S"),"%Y-%m-%d %H:%M:%S")

Is there a simpler way to end up with a datetime.datetime object for mongoDB than this?

now = datetime.now().replace(microsecond=0) – Waqas Aug 10 '21 at 14:43 — Waqas, Aug 10 '21 at 14:43

score 213 · Accepted Answer · answered Jul 18 '15 at 04:20

213

You can use datetime.replace() method -

>>> d = datetime.datetime.today().replace(microsecond=0)
>>> d
datetime.datetime(2015, 7, 18, 9, 50, 20)

answered Jul 18 '15 at 04:20

Anand S Kumar

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This question is old, but I would like to add that you would need to do something like this if you intend to keep milliseconds `now = datetime.utcnow()` `now.replace(microsecond=round(now.microsecond, -3))` – Curt Mar 19 '22 at 16:34

simple way to drop milliseconds from python datetime.datetime object

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