Removing an entry in r

Question

In SAS there is the capability to remove an observation through a simple if statement. For instance if I wanted to delete the rows where Year = #. I could write:

If year == "#" then delete;

Is there an equivalent way in r? I tried this:

 DF<- DF[!(DF$Year == "#"),]

Data set in R:

Year        Month
#           June
#           July 
#           August
2015        August

But when I run DF$year, I still get # as a factor level when I thought it would be filtered out?

You're doing it right. It will still be a factor level, that doesn't mean it actually exists in the vector `DF$year`. You can drop the extra factor level if you need to with `droplevels` or by using factor again `DF$year — Brandon Bertelsen, Jul 17 '15 at 23:20
Yeah, I ran is.numeric(DF2$Year) and it returned false, so how to get rid of those non-numerics..Thanks — steppermotor, Jul 17 '15 at 23:29
Well, a factor isn't numeric. It can be converted to numeric with `as.numeric(as.character(your_factor))`. You should open a new question with your next question, please make a reproducible example (see: http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example) — Brandon Bertelsen, Jul 17 '15 at 23:30
Factors are factors, they are not numbers/numeric. Try translating them into numbers and see if it works: as.numeric(as.character(DF2$Year)) — Sharon, Jul 17 '15 at 23:30

score 3 · Accepted Answer · answered Jul 17 '15 at 23:32

You're doing it right. It will still be a factor level, that doesn't mean it actually exists in the vector DF$year. You can drop the extra factor level if you need to with droplevels or by using factor again DF$year <- factor(DF$year)

If you need to convert a factor with numeric labels to a numeric vector, you can use:

as.numeric( ## convert to numeric as expected
  as.character( ## because factors are numbers with labels
    your_factor 
    )
  )
)

Removing an entry in r

1 Answers1