PHP while function not working

Question

I got this simple code:

$x = 1999;
while($x != 1949)
{
    echo '<option value="' $x '">' $x '</option>';
    $x = $x - 1;
}

But the page isn't loading any more with this code, what's wrong with it?

score 0 · Accepted Answer · answered Jul 16 '15 at 12:04

0

You need to concatenate your variables: (notice the dots in your echo)

$x = 1999;
while($x != 1949)
{
    echo '<option value="'.$x.'">'.$x.'</option>';
    $x = $x - 1;
}

answered Jul 16 '15 at 12:04

Daan

Damn I forgot the dots :(( thx.. – donbingo Jul 16 '15 at 12:07
Please mark this question to be deleted – donbingo Jul 16 '15 at 12:08
You can delete it yourself @donbingo – Jay Blanchard Jul 16 '15 at 12:10
I can only flag it for moderation because it contains answers – donbingo Jul 16 '15 at 12:12

score 0 · Answer 2 · answered Jul 16 '15 at 12:04

0

try this

$x = 1999;
while($x != 1949)
{
    echo '<option value="'. $x .'">'. $x .'</option>';
    $x = $x - 1;
}

answered Jul 16 '15 at 12:04

score 0 · Answer 3 · answered Jul 16 '15 at 12:05

0

Try

$x = 1999;
while($x != 1949)
{
    echo '<option value="'.$x .'">'. $x. '</option>';
    $x--;
}

answered Jul 16 '15 at 12:05

Dhinju Divakaran

3 Answers3