How does System.out.println() works on binary data?

Question

I am unable to understand the output of the below code

package beg;

import java.util.*;
import java.io.*;
public class Hell
{
    public static void main(String[] args)
    {
        System.out.println(10+010); //Prints 18
        System.out.println(010+010); //Prints 16
        System.out.println(010+10); //Prints 18
    }
}

Can somebody please explain?

When you add a `0` infront of a integer literal, its considered a `Octal` number. Hence `010` is `8` in decimal. — Codebender, Jul 07 '15 at 06:26
A number starting with 0 is written using octal notation. So 010 = 1x8 + 0 = 8. — Michel Billaud, Jul 07 '15 at 06:26

score 4 · Answer 1 · answered Jul 07 '15 at 06:27

4

When you write 010 its octal code... not binary

System.out.println(10+010); 
System.out.println(010+010); 
System.out.println(010+10);

These above lines are equivalent to:

System.out.println(10+8); // 010 being code for 8
System.out.println(8+8); 
System.out.println(8+10)

answered Jul 07 '15 at 06:27

CoderNeji

2,006
3
19
31

@CoderNeji-Got it bro,thanks a lot – Frosted Cupcake Jul 07 '15 at 06:33

score 0 · Answer 2 · answered Jul 07 '15 at 06:28

0

This is not binary its summation of octal numbers. In java number started by 0 are octal. And output is in decimal.

010 = 8 .

System.out.println(10+010);

10 + 8

System.out.println(010+010);

8 + 8

System.out.println(010+10);

8 + 10

answered Jul 07 '15 at 06:28

Panther

3,224
9
26
48

How does System.out.println() works on binary data?

2 Answers2