Javascript Issue Checking if Value is Even

Question

I'm trying to write a function that checks whether a value is odd or even, but it isn't quite working as it should, or rather, at all.

The code I got was from this question.

        function isEven(value) {
            if (value % 2 == 0) {
                return true;
                console.log("True");
            }
            else {
                return false;
                console.log("False");
            }
            console.log(value);
        }

        isEven(3);

I get no errors in the browser's console, but it also does not log True, False, or value.

Note: I will also accept jQuery solutions, but would prefer Javascript.

also once you are convinced this is the behavior that you want. Instead of returning bool constants return what you are checking. e.g. `function isEven (value) { return value % 2 === 0; }` — t3dodson, Jul 03 '15 at 03:57

score 2 · Accepted Answer · answered Jul 03 '15 at 03:55

2

You are returning before logging. Anything after return will not be executed.

return after logging

 function isEven(value) {
   if (value % 2 == 0) {
     console.log("True");
     return true;
   } else {
     console.log("False");
     return false;
   }
 }

 isEven(3);

answered Jul 03 '15 at 03:55

AmmarCSE

29,061
5
39
52

I feel really stupid now >.< That worked, thanks for the help. – unironicallyironic Jul 03 '15 at 04:13
@Calebbait, don't. Ive made far sillier mistakes. Glad it helped :) – AmmarCSE Jul 03 '15 at 04:18

score 0 · Answer 2 · answered Jul 03 '15 at 04:07

0

Ensure value is an integer first by parsing it with

parseInt(value)

answered Jul 03 '15 at 04:07

omikes

7,248
8
36
47

Javascript Issue Checking if Value is Even

2 Answers2