Start processing files from N-th file in folder

Question

I am using Python to process over 100.000 text files which are in a folder:

for f in glob.glob("/folder_path/*.txt"):
 with open(f) as inputfile:

Is there a way to start processing from the N-th file in the folder (let's say from the 30.000 th file in the folder), instead of starting over from the 1st file every time in the folder?

I know I can move the files I don't want to process in another file, but since the files are very big it is not a good idea to do that every time, so I would like to have a way to choose which file to start from programmatically...

Can't you store the file list ahead of the for loop. Then, start the for loop at the Nth file? So instead of "for f in glob..." you store the list "files = glob..." and then start the loop at the Nth element of this list? — jesperk.eth, Jun 29 '15 at 12:17

score 3 · Accepted Answer · edited May 23 '17 at 12:14

3

Slice notation can be used in this case:

for f in glob.glob(...)[n:]:
    with open(f) as inputfile:

edited May 23 '17 at 12:14

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answered Jun 29 '15 at 14:16

kylieCatt

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Start processing files from N-th file in folder

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