How to force a GSON deserialization exception when a field is not present without a custom deserialization?

Question

I want to be able to check if a certain field is present in my response, and in case it is not present I would like to get an exception.

is there a way to force a GSON deserialization to throw an exception when a field is not present without a custom deserialization?

Have you read [this](http://stackoverflow.com/questions/3163193) and [this](https://sites.google.com/site/gson/gson-design-document)? — Bernd Linde, Jun 19 '15 at 14:01

score 0 · Answer 1 · edited May 23 '17 at 12:30

0

I've done something like this in the past. Registering a TypeAdapter seems to be a decent solution

edited May 23 '17 at 12:30

Community

answered Jun 19 '15 at 14:21

Shaun

1 Answers1