Python: Sorting dictionary by key

Question

I am trying to sort a dictionary by key.

If I do the following, then the dictionary is sorted like this

Instead, I wanted to sort it like the following:

My existing code

writer = csv.writer(open('something.csv', 'wb'))

keylist = count.keys()
keylist.sort()
for key in keylist:
    writer.writerow([key, count[key]])

It looks like your keys are strings, rather than numbers - that's lexicographical sorting. — jonrsharpe, Jun 09 '15 at 20:21
Anyways I think such questions are already there on stackoverflow. — Aditya, Jun 09 '15 at 20:44
You can simply `keylist.sort(key=int)`, you could also pass sorted to writerows `writer.writerows(sorted(count.items(),key=lambda x: int(x[0])))` — Padraic Cunningham, Jun 09 '15 at 20:44

score 2 · Accepted Answer · answered Jun 09 '15 at 20:23

2

Your dictionary keys are strings, so they are sorted alphabetically. You need to convert the keys to integers first:

keylist = [int(k) for k in count.keys()]
keylist.sort()

for key in keylist:
     writer.writerow([key, count[str(key)]])

answered Jun 09 '15 at 20:23

poke

`count.keys(key=int)` would be work as the OP does not need ints and you would not have to cast again, you could also just iterate over the dict. – Padraic Cunningham Jun 09 '15 at 20:51

1 Answers1