Python closure not acting as expected

Question

The following Python code:

def foo():
    t = []
    for i in range(1, 3):
        def bar():
            return i * i
        t.append(bar)
    return t

for f in foo():
    print(f())

Outputs: 4 4. Why isn't the first call output 1? I thought the closure bar() could save the current value of i.

---

BTW, the almost equivalent Lua code:

function foo()
    local t = {}
    for i = 1, 2 do
        local bar = function() return i * i end
        table.insert(t, bar)
    end
    return t
end

for _, f in ipairs(foo()) do
    print(f())
end

Outputs 1 4 as what I expected.