Powershell function with two argument give takes one argument

Question

I define the powershell function as below

function t ($a , $b ) {
    write-Host '1-', $a
    write-Host '2-', $b
}

When calling t(4,5) give

1- 4 5
2-

instead of natural

1- 4
2- 5

How can I get the second?

PowerShell separates function arguments with spaces, not commas. look at the gotcha here http://stackoverflow.com/tags/powershell/info — Loïc MICHEL, May 20 '15 at 11:10

score 1 · Accepted Answer · answered May 20 '15 at 12:27

1

Kayasax has answered the question in his comment. Function calls do not require parens around the argument(s).

call with

t 4 5

instead of what you did.

answered May 20 '15 at 12:27

Walter Mitty

1 Answers1