How do I iterate through children elements of a div using jQuery?

Question

I have a div and it has several input elements in it... I'd like to iterate through each of those elements. Ideas?

Answer 1

Use children() and each(), you can optionally pass a selector to children

$('#mydiv').children('input').each(function () {
    alert(this.value); // "this" is the current element in the loop
});

You could also just use the immediate child selector:

$('#mydiv > input').each(function () { /* ... */ });

Answer 2

It is also possible to iterate through all elements within a specific context, no mattter how deeply nested they are:

$('input', $('#mydiv')).each(function () {
    console.log($(this)); //log every element found to console output
});

The second parameter $('#mydiv') which is passed to the jQuery 'input' Selector is the context. In this case the each() clause will iterate through all input elements within the #mydiv container, even if they are not direct children of #mydiv.

Answer 3

If you need to loop through child elements recursively:

function recursiveEach($element){
    $element.children().each(function () {
        var $currentElement = $(this);
        // Show element
        console.info($currentElement);
        // Show events handlers of current element
        console.info($currentElement.data('events'));
        // Loop her children
        recursiveEach($currentElement);
    });
}

// Parent div
recursiveEach($("#div"));   

---

NOTE: In this example I show the events handlers registered with an object.

Answer 4

$('#myDiv').children().each( (index, element) => {
    console.log(index);     // children's index
    console.log(element);   // children's element
 });

This iterates through all the children and their element with index value can be accessed separately using element and index respectively.

Answer 5

It can be done this way as well:

$('input', '#div').each(function () {
    console.log($(this)); //log every element found to console output
});

Answer 6

I don't think that you need to use each(), you can use standard for loop

var children = $element.children().not(".pb-sortable-placeholder");
for (var i = 0; i < children.length; i++) {
    var currentChild = children.eq(i);
    // whatever logic you want
    var oldPosition = currentChild.data("position");
}

this way you can have the standard for loop features like break and continue works by default

also, the debugging will be easier

Answer 7

children() is a loop in itself.

$('.element').children().animate({
'opacity':'0'
});

Answer 8

It's working with .attr('value'), for elements attributes

$("#element div").each(function() {
   $(this).attr('value')
});