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I know how to use python to report exact match in a string:

import re
word='hello,_hello,"hello'
re.findall('\\bhello\\b',word)
['hello', 'hello']

How do I report the indices of the exact matches? (in this case, 0 and 14)

tzaman
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Sirian
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  • Check out this link. Similar question http://stackoverflow.com/questions/4664850/find-all-occurrences-of-a-substring-in-python – Saicharan S M Apr 22 '15 at 21:12
  • possible duplicate of [Find the indexes of all regex matches in Python?](http://stackoverflow.com/questions/3519565/find-the-indexes-of-all-regex-matches-in-python) – HamZa Apr 22 '15 at 22:02

2 Answers2

1

Use finditer:

[(g.start(), g.group()) for g in re.finditer('\\b(hello)\\b',word)]
# [(0, 'hello'), (14, 'hello')]
tzaman
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  • @Sirian feel free to [vote up and accept](http://stackoverflow.com/help/someone-answers) it then. Cheers! – tzaman Apr 23 '15 at 18:10
1

instead use word.find('hello',x)

word = 'hello,_hello,"hello'
tmp = 0
index = [] 
for i in range(len(word)):
   tmp = word.find('hello', tmp)
   if tmp >= 0:
       index.append(tmp)
       tmp += 1
Max
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  • `str.find` will return all occurrences, without respecting the word boundary condition as desired in the question. – tzaman Apr 22 '15 at 21:20