Operator overloading

Question

Java doesn't support operator overloading. If so then in the following code:

System.out.println( "I am" + "a programmer");

+ is concatenating string.

Isn't it operator overloading?

It is called method overloading. https://docs.oracle.com/javase/tutorial/java/javaOO/methods.html — giannis christofakis, Apr 14 '15 at 13:47
System.out.println( "I am" + "a programmer"); here + is overloaded operator. — Seemab, Apr 14 '15 at 18:17
It is indeed (or if it is not it's a strict equivalent) but java doesn't allow you to do the same for your classes for some weird nonsense reasons. — Vivick, Apr 15 '17 at 19:39

score 2 · Answer 1 · answered Apr 14 '15 at 12:58

These are println methods in PrintStream class

 public void println(int x) {
        synchronized (this) {
            print(x);
            newLine();
        }
    }

public void println(String x) {
    synchronized (this) {
        print(x);
        newLine();
    }
}

so println(2+3) means println(5) and it calls println(int x)

Operator overloading

1 Answers1