JavaScript array contains one of value

Question

Example array:

var array1 = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n"];

Array with requires:

var array2 = ["d", "g", "j", "k"];

So it will return true if array1 contains at least one value from array2. Can you help me with that?

Note: array1 may contains all four values from array2.

Answer 1

You could try something as simple as:

function Contains(array1, array2)
{
    for(var i=0; i<array2.length; i++)
        if(array1.indexOf(array2[i])>-1)
            return true;

    return false;
}

Initially you loop through the items of array2. If one item of array2 is found in the array1 you return true. Otherwise you return false.

Answer 2

for(var i = 0; i < array1.length; i++) {
    for(var j = 0; j < array2.length; j++) {
        if(array1[i] === array2[j]) {
            return true
        }
    }
}
return false;

Answer 3

var count = array2.length;

for (var i = 0; i < count; i++) {

    if (array1.indexOf(array2[i] !== -1) {
        return true;
    }

}