How to create a array of elements in range?

Question

In Java, is there any way to create a array of elements in range?

For example,

new int[] {1:10}, which should be equivalent to,
new int[] {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

I was thinking, if we need to create a array of large range elements (5-1000), rather than writing it like 5, 6, ..., 1000, if there is way like 5:1000.

score 8 · Answer 1 · answered Apr 02 '15 at 09:59

8

In Java 8

int[] array = IntStream.rangeClosed(1, 10).toArray();

answered Apr 02 '15 at 09:59

Reimeus

155,977
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Great this is, alas I'm using Java 7 environment in production! – unknown_boundaries Apr 02 '15 at 10:02

score 1 · Answer 2 · answered Apr 02 '15 at 09:58

1

There is not a built-in language feature, but you can easily create a method that does it:

public static int[] createIntRangeArray(int start, int end) {
    int[] result = new int[end-start+1];
    for(int i = start; i <= end; i++)
        result[i-start] = i;
    return result;
}

and then:

createIntRangeArray(1, 10)
// is equivalent to
new int[] {1,2,3,4,5,6,7,8,9,10}

answered Apr 02 '15 at 09:58

user253751

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There may be a built-in *method* that I'm not aware of, especially with Java 8 streams. – user253751 Apr 02 '15 at 09:58

Nielarshi · Answer 3 · 2015-04-02T10:15:32.993

1

class ArrayGenerator {
    public static int[] generateArray(int start, int end) {
        int[] array = new int[end-start+1];
        for(int i=start;i<=end;i++) {
            array[i-start] = i;
        }
        return array;
    }
}

//this can be used like

    int start = 5;
    int end = 10;
    int[] generatedArray = ArrayGenerator.generateArray(start,end);

    for(int i : generatedArray) {
        System.out.println(i);
    }

edited Apr 02 '15 at 10:15

answered Apr 02 '15 at 09:59

Nielarshi

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The range has start and end indices. You should not assume it to be starting with 0 always. – unknown_boundaries Apr 02 '15 at 10:09
Ya, got it. Have changed now. :) Thanks – Nielarshi Apr 02 '15 at 10:16

score 1 · Answer 4 · answered Apr 02 '15 at 10:01

Consider writing a separate method containing a loop which initializes your array.

public int[] createArrayWithRange(int startIncl, int endIncl) {
    int[] nums = new int[endIncl - startIncl + 1];
    for (int i = 0; i < (endIncl - startIncl + 1) ; i++) {
        nums[i] = i + startIncl;
    }
    return nums;
}

score 0 · Answer 5 · answered Apr 02 '15 at 11:13

My proposition:

public List<Integer> generateIntTab(int size){
        List<Integer> x = new ArrayList<Integer>();
        for(int i = 0 ; i < size; i++){
            x.add((i << 1)-i+1);
        }
        return x;
    }

Its a bit slower then standard JDK8 function which give @Reimeus

How to create a array of elements in range?

5 Answers5