I'm pretty new to c++, i'm now trying to learn all the basics, I know when default constructors are called, but when i tried different syntax it doesn't work like i expected.
Look at the following code:
class a;
class b();
class c(NULL);
'class' is a class i created with default constructor, for a and c everything works well, but for b it just won't recognize the variable as a class member.
As i see it b and c are basically the same, what's wrong than? Thanks!
Don't name your class "class", as it is a reserved name.
As for C++, if the constructor takes no parameters, you instantiate it using
Foo a; // note, if you are using c++11, you can do Foo a{};
As opposed to:
Foo b();
Which actually does something totally unexpected*, and declares a function named b that returns a Foo instance.
As for Foo c(null), it won't compile as there is no default constructor that takes an argument.
* It is referred to as "the most vexing parse", though I find that to be an exaggeration. It can certainly catch you by surprise, but just knowing that you can declare a function prototype inside a function, should be enough to remove the "vexing" aspect.
In other words int getMyInt(); is obviously a function prototype when placed outside any function definitions. However, since this is also the case when inside a function definition, int getMyInt(); doesn't do anything it wouldn't normally do... which is to define a function prototype getMyInt that returns an integer.
b is interpreted as a declaration of a function taking no arguments and returning an object of type class.
This is known as the most vexing parse. Edit: This is not the most vexing parse.
you meant something like this? NULL represents 0, you know. void means no data.
class Cl_Test
{
private:
int m_a;
public:
Cl_Test(int in_a= -1) { m_a= in_a; }
};
int main(int argc, char** argv) {
Cl_Test a;
Cl_Test b();
Cl_Test c(void);
return 0; }
edit:
my mistakes:
