I want to write a stored procedure that gets an array as input parameter and sort that array and return the sorted array.
Kindly help.
I want to write a stored procedure that gets an array as input parameter and sort that array and return the sorted array.
Kindly help.
The best way to sort an array of integers is without a doubt to use the intarray extension, which will do it much, much, much faster than any SQL formulation:
CREATE EXTENSION intarray;
SELECT sort( ARRAY[4,3,2,1] );
A function that works for any array type is:
CREATE OR REPLACE FUNCTION array_sort (ANYARRAY)
RETURNS ANYARRAY LANGUAGE SQL
AS $$
SELECT ARRAY(SELECT unnest($1) ORDER BY 1)
$$;
(I've replaced my version with Pavel's slightly faster one after discussion elsewhere).
In PostrgreSQL 8.4 and up you can use:
select array_agg(x) from (select unnest(ARRAY[1,5,3,7,2]) AS x order by x) as _;
But it will not be very fast.
In older Postgres you can implement unnest like this
CREATE OR REPLACE FUNCTION unnest(anyarray)
RETURNS SETOF anyelement AS
$BODY$
SELECT $1[i] FROM
generate_series(array_lower($1,1),
array_upper($1,1)) i;
$BODY$
LANGUAGE 'sql' IMMUTABLE
And array_agg like this:
CREATE AGGREGATE array_agg (
sfunc = array_append,
basetype = anyelement,
stype = anyarray,
initcond = '{}'
);
But it will be even slower.
You can also implement any sorting algorithm in pl/pgsql or any other language you can plug in to postgres.
Just use the function unnest():
SELECT
unnest(ARRAY[1,2]) AS x
ORDER BY
x DESC;
See array functions in the Pg docs.
This worked for me from http://www.pgsql.cz/index.php/PostgreSQL_SQL_Tricks_I#General_array_sort
CREATE OR REPLACE FUNCTION array_sort (ANYARRAY)
RETURNS ANYARRAY LANGUAGE SQL
AS $$
SELECT ARRAY(
SELECT $1[s.i] AS "foo"
FROM
generate_series(array_lower($1,1), array_upper($1,1)) AS s(i)
ORDER BY foo
);
$$;
Please see Craig's answer since he is far more more knowledgable on Postgres and has a better answer. Also if possible vote to delete my answer.
Very nice exhibition of PostgreSQL's features is general procedure for sorting by David Fetter.
CREATE OR REPLACE FUNCTION array_sort (ANYARRAY)
RETURNS ANYARRAY LANGUAGE SQL
AS $$
SELECT ARRAY(
SELECT $1[s.i] AS "foo"
FROM
generate_series(array_lower($1,1), array_upper($1,1)) AS s(i)
ORDER BY foo
);
$$;
If you're looking for a solution which will work across any data-type, I'd recommend taking the approach laid out at YouLikeProgramming.com.
Essentially, you can create a stored procedure (code below) which performs the sorting for you, and all you need to do is pass your array to that procedure for it to be sorted appropriately.
I have also included an implementation which does not require the use of a stored procedure, if you're looking for your query to be a little more transportable.
Creating the stored procedure
DROP FUNCTION IF EXISTS array_sort(anyarray);
CREATE FUNCTION
array_sort(
array_vals_to_sort anyarray
)
RETURNS TABLE (
sorted_array anyarray
)
AS $BODY$
BEGIN
RETURN QUERY SELECT
ARRAY_AGG(val) AS sorted_array
FROM
(
SELECT
UNNEST(array_vals_to_sort) AS val
ORDER BY
val
) AS sorted_vals
;
END;
$BODY$
LANGUAGE plpgsql;
Sorting array values (works with any array data-type)
-- The following will return: {1,2,3,4}
SELECT ARRAY_SORT(ARRAY[4,3,2,1]);
-- The following will return: {in,is,it,on,up}
SELECT ARRAY_SORT(ARRAY['up','on','it','is','in']);
Sorting array values without a stored procedure
In the following query, simply replace ARRAY[4,3,2,1] with your array or query which returns an array:
WITH
sorted_vals AS (
SELECT
UNNEST(ARRAY[4,3,2,1]) AS val
ORDER BY
val
)
SELECT
ARRAY_AGG(val) AS sorted_array
FROM
sorted_vals
... or ...
SELECT
ARRAY_AGG(vals.val) AS sorted_arr
FROM (
SELECT
UNNEST(ARRAY[4,3,2,1]) AS val
ORDER BY
val
) AS vals
I'm surprised no-one has mentioned the containment operators:
select array[1,2,3] <@ array[2,1,3] and array[1,2,3] @> array[2,1,3];
?column?
══════════
t
(1 row)
Notice that this requires that all elements of the arrays must be unique.
(If a contains b and b contains a, they must be the same if all elements are unique)