Python : list of int to a function waiting for int

Question

I have a function f(a,b,c) waiting for 3 int. I have a list t = list(1,2,3) that i want to input to f : f(t). But it doesn't work. What is the easiest way to do it.

EDIT : t = list('1','2','3')

Thank you

Avinash Raj · Accepted Answer · 2015-03-10T14:14:10.033

5

You need to unpack the values present in list t.

 f(*t)

Example:

>>> def f(a,b,c):
        print(a,b,c)

>>> t = [1,2,3]
>>> f(*t)
1 2 3

OR

>>> def f(a,b,c):
        print(a,b,c)


>>> t = ['1','2','3']
>>> f(*map(int,t))
1 2 3

edited Mar 10 '15 at 14:14

answered Mar 10 '15 at 13:27

Avinash Raj

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What if a,b,c are strings and i want to change them in the same time to integers ? – The Answer Mar 10 '15 at 13:35
@TheAnswer check my update.. – Avinash Raj Mar 10 '15 at 14:14
Will the code break if the list has only 2 items (and `c` doesn't have a default value)? Just curious. – Eduard Luca Mar 10 '15 at 14:19
yep, because the defined function needs exactly three parameters. You could set the default value of c like `def f(a,b,c=0):` – Avinash Raj Mar 10 '15 at 14:20

score 0 · Answer 2 · answered Mar 10 '15 at 13:28

0

You will have to pass the values as follows:

f(t[0], t[1], t[2])

answered Mar 10 '15 at 13:28

Mo H.

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score 0 · Answer 3 · answered Mar 10 '15 at 13:30

0

You can call the function like this:

f(t[0],t[1],t[2])

Cheers!

answered Mar 10 '15 at 13:30

Wealot

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Python : list of int to a function waiting for int

3 Answers3