creating large array in C but cant access memory

Question

I am currently creating a large array that looks like this:

unsigned char arr[35000][500];

I then try to write in 256 characters into the array like so:

for(i=0; i < 256; i++)
{
  arr[i][0] = i;
}

When I do this, I get the following seg fault:

Program received signal SIGSEGV, Segmentation fault.
0x00000000004007e3 in main () at arr.c:41
41        arr[i][0] = i;

Any suggestions on why this is happening?

This is because of stack overflow. Take out of `main` or use dynamic memory allocation. Read this [answer](http://stackoverflow.com/a/28462111/2455888) for further explanation. — haccks, Feb 11 '15 at 19:29
As @haccks said --- you are trying to allocate (roughly) 17MB of memory on the stack. — Tim Čas, Feb 11 '15 at 19:30

score 1 · Answer 1 · answered Feb 11 '15 at 19:30

1

You probably have some stack overflow happening. Consider using dynamic memory allocation

answered Feb 11 '15 at 19:30

sedavidw

1 Answers1