c++ delete a newed array by using delete[]

Question

I know in c++ delete a newed array by using delete[]. What I am wondering is, what if I just do delete without []. I saw something like this in our company code. And it does no crash the system. Is this also right?

u_char* binBuf2 = new u_char[bitCount + 1];
delete binBuf2;

thanks

Also http://stackoverflow.com/questions/1553382/is-delete-equal-to-delete/1553407#1553407 — Cory Kramer, Feb 04 '15 at 21:10
it is not correct, but it will work anyways, on *some* platforms. Dont use — sp2danny, Feb 04 '15 at 21:10
_" I saw something like this in our company code."_ That sounds highly questionable, and should be fixed. — πάντα ῥεῖ, Feb 04 '15 at 21:16

score 1 · Answer 1 · answered Feb 04 '15 at 21:10

1

No that is not the correct method of freeing up the memory.

Keep in mind that because something doesn't crash the system doesn't mean it's good practice

answered Feb 04 '15 at 21:10

sedavidw

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(or even correct, sensible, defined, reproducible, or any combination thereof) – Quentin Feb 04 '15 at 21:27

c++ delete a newed array by using delete[]

1 Answers1