How to modify a date/time variable in PHP

Question

I am receiving the variable $CheckIn $CheckIn is a date in Y-m-d format, how can i create a $Checkout variable with the value +8 days after checkin.

Looks like a duplicate of : http://stackoverflow.com/questions/3727615/adding-days-to-date-in-php — CD001, Jan 27 '15 at 13:00

score 3 · Answer 1 · answered Jan 27 '15 at 12:52

3

Try this:

$Date = "2010-09-17";
echo date('Y-m-d', strtotime($Date. ' + 8 days'));//save this in any variable

answered Jan 27 '15 at 12:52

Manwal

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score 3 · Accepted Answer · answered Jan 27 '15 at 12:53

3

$checkout = date('Y-m-d', strtotime($checkin. ' + 8 days'));

answered Jan 27 '15 at 12:53

Christian Hagdorn

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score 0 · Answer 3 · answered Jan 27 '15 at 12:55

0

With DateTime()

$date = new DateTime($checkin);
$date->modify('+8 days');
echo $date->format('Y-m-d');

answered Jan 27 '15 at 12:55

Rakesh Sharma

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How to modify a date/time variable in PHP

3 Answers3