DateTimeFormatter Support for Single Digit Day of Month and Month of Year

Question

DateTimeFormmater doesn't seem to handle single digit day of the month:

String format = "MM/dd/yyyy";
String date   = "5/3/1969";
System.out.println(new SimpleDateFormat(format).parse(date));
System.out.println(LocalDate.parse(date, DateTimeFormatter.ofPattern(format)));

In this example, SimpleDateFormat correctly parses the date, but DateTimeFormatter throws an exception. If I were to use zero padded dates, e.g., "05/03/1969", both work. However, if either the day of month or the month of year are single digit, then DateTimeFormatter throws an exception.

What is the right DateTimeFormatter format to parse both one and two digit day of month and month of year?

Have you resolved this issue? I'm also looking into a java8 solution to parse 1 or 2 digits month, or 2 or 4 digits year. — user607455, Mar 12 '15 at 15:52

score 104 · Answer 1 · answered Dec 19 '14 at 18:47

104

From the documentation:

Number: If the count of letters is one, then the value is output using the minimum number of digits and without padding.

So the format specifier you want is M/d/yyyy, using single letter forms. Of course, it will still parse date Strings like "12/30/1969" correctly as for these day/month values, two digits are the “minimum number of digits”.

The important difference is that MM and dd require zero padding, not that M and d can’t handle values greater than 9 (that would be a bit… unusual).

answered Dec 19 '14 at 18:47

Holger

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I faced the same issue in Dart, but with above solution implemented using intl package, it is working properly now. Thank you. – Raja C Jun 30 '20 at 16:15
This one worked, well explained @Holger. Link for documentation was helpful too. – Vishwas Shenoy Alevoor Dec 14 '21 at 18:18

Joginder Malik · Answer 2 · 2021-02-22T17:58:11.917

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In Java 8 Date Time API, I recently used

DateTimeFormatter formatter = new DateTimeFormatterBuilder()
            .appendOptional(DateTimeFormatter.ofPattern("M/dd/yyyy"))
            .toFormatter();

System.out.println(LocalDate.parse("10/22/2020", formatter));
System.out.println(LocalDate.parse("2/21/2020", formatter));

edited Feb 22 '21 at 17:58

answered Feb 05 '20 at 19:07

Joginder Malik

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Why include the second pattern? What value would you expect to be parsed by the second but not the first? – Jon Skeet Feb 15 '21 at 16:30
@JonSkeet very good suggestion by you. I have just removed the second pattern as single pattern is able to parse both type of values like 10/22/2020 and 2/22/2020 – Joginder Malik Feb 22 '21 at 18:00
this is an great solution. I could add multiple patterns. thanks – user7510999 Oct 11 '21 at 14:43

score 2 · Answer 3 · answered Dec 07 '21 at 12:04

The best approach to deal with this kind of problem , That is number of different digits in Date (in day , month or year ) is to use this pattern : (M/d/[uuuu][uu]) .

Example:

String date = "7/7/2021"; // or "07/07/2021" or "07/7/21" etc
LocalDate localDate = LocalDate.parse(
date,DateTimeFormatter.ofPattern("M/d/[uuuu][uu]"));

Here uuuu/uu handle four and two digits year.

DateTimeFormatter Support for Single Digit Day of Month and Month of Year

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