eliminate duplication in jquery array

Asked Dec 07 '14 at 23:31

Active Dec 08 '14 at 00:18

Viewed 23 times

I am new to jquery, please i need some help.

I want to eliminate the duplication in arrays, below is my function:

    function unique(list) {
      var result = [];
      $.each(list, function(i, e) {
          if ($.inArray(e, result) == -1) { result.push(e); }
          else {}
      });
      return result;
    }

It works well with duplicated arrays but when I use it for one without duplicated content it returns a string.

For example if my array is [1, 2, 2, 3, 1] ==> it returns [1, 2, 3]

But when a I have like this array [1, 2] ==> it returns 12

(I need to return an array [1, 2]). I want to known how can I correct it.

Thanks.

edited Dec 08 '14 at 00:18

Robbie

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asked Dec 07 '14 at 23:31

user2842247

It seems to work for me... http://jsfiddle.net/s1wbpqhe/ – Totò Dec 07 '14 at 23:40
and you can get rid of the empty else BTW – Totò Dec 07 '14 at 23:40
http://jsfiddle.net/zh089ff9/ for me it also works – user2167382 Dec 07 '14 at 23:42
It's very likely that your issue is in the code that uses that function. If you want to put it up somebody may be able to help you. – Totò Dec 07 '14 at 23:44
Should be noted that jQuery already has a [**unique()**](http://api.jquery.com/jquery.unique/) method built in for DOM nodes ? – adeneo Dec 07 '14 at 23:52
... and that the native `Array.reduce` can do this faster and with less code for arrays that don't contain DOM nodes. – adeneo Dec 07 '14 at 23:55
1

http://stackoverflow.com/questions/13486479/how-to-get-an-array-of-unique-values-from-an-array-containing-duplicates-in-java – adeneo Dec 07 '14 at 23:56

eliminate duplication in jquery array

0 Answers0