Convert a list of integers to string

Question

I want to convert my list of integers into a string. Here is how I create the list of integers:

new = [0] * 6
for i in range(6):
    new[i] = random.randint(0,10)

Like this:

new == [1,2,3,4,5,6]
output == '123456'

`new = [ random.randint(0,10) for i in range(6) ]` would be simpler. — chepner, Nov 17 '14 at 19:22

score 57 · Answer 1 · edited May 23 '17 at 12:03

57

With Convert a list of characters into a string you can just do

''.join(map(str,new))

edited May 23 '17 at 12:03

Community

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1

answered Nov 17 '14 at 18:30

tynn

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3

Or for the `map`-averse, `''.join([str(x) for x in new])`. – chepner Nov 17 '14 at 19:23
2

Or even `''.join(str(random.randint(0, 10)) for i in range(10))` – Chinmay Kanchi Nov 17 '14 at 19:29

jgritty · Accepted Answer · 2014-11-17T18:33:18.247

14

There's definitely a slicker way to do this, but here's a very straight forward way:

mystring = ""

for digit in new:
    mystring += str(digit)

edited Nov 17 '14 at 18:33

answered Nov 17 '14 at 18:26

jgritty

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score 8 · Answer 3 · answered Jul 20 '19 at 12:57

8

two simple ways of doing this

"".join(map(str, A))
"".join([str(a) for a in A])

answered Jul 20 '19 at 12:57

Satyam Singh

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score 1 · Answer 4 · edited May 23 '17 at 12:10

Coming a bit late and somehow extending the question, but you could leverage the array module and use:

from array import array

array('B', new).tobytes()

b'\n\t\x05\x00\x06\x05'

In practice, it creates an array of 1-byte wide integers (argument 'B') from your list of integers. The array is then converted to a string as a binary data structure, so the output won't look as you expect (you can fix this point with decode()). Yet, it should be one of the fastest integer-to-string conversion methods and it should save some memory. See also documentation and related questions:

https://www.python.org/doc/essays/list2str/

https://docs.python.org/3/library/array.html#module-array

Converting integer to string in Python?

Maybe python 3 only? tobytes not available for me in python 2. — Samuel, Jan 02 '21 at 20:57

score 1 · Answer 5 · answered Oct 18 '21 at 17:51

1

If you don't like map():

new = [1, 2, 3, 4, 5, 6]

output = "".join(str(i) for i in new)
# '123456'

Keep in mind, str.join() accepts an iterable so there's no need to convert the argument to a list.

answered Oct 18 '21 at 17:51

Paul P

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score -3 · Answer 6 · answered Oct 23 '18 at 05:37

-3

You can loop through the integers in the list while converting to string type and appending to "string" variable.

for int in list:
    string += str(int)

answered Oct 23 '18 at 05:37

Cherry

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Its totally different – Cherry Oct 23 '18 at 06:59
in what way, can you please help me. – dkb Oct 23 '18 at 08:25
@Cherry your code is exactly the same, changing variable names does not make the code different – WhatsThePoint Mar 25 '19 at 13:55
Plus, this is very bad practice. Never use reserved names as variable names. – Fejs Mar 25 '19 at 14:10
@WhatsThePoint Its different, its just that you cannot see – Cherry Jul 16 '19 at 07:35
@Fejs Thats how you code and this is how i code, not a bad practice in my perspective – Cherry Jul 16 '19 at 07:36
Please read this short answer: https://www.quora.com/What-is-the-difference-between-reserved-word-and-variable-name There is no perspective, that's the fact. – Fejs Jul 16 '19 at 07:42
@Fejs Theres a perspective for everything on how you see things. – Cherry Jul 17 '19 at 04:32

Convert a list of integers to string

6 Answers6