Arithmetic Operator Overloading C++

Question

I am new to C++ and am trying to understand overloading to get my arithmetic operators to overload successfully. Here is the code that doesn't compile.

ComplexNumber ComplexNumber::operator*(const ComplexNumber& rightOp) const
{
double newValue = realNumberValue * rightOp.realNumberValue;
return ComplexNumber(newValue);
}

possible duplicate of [Operator overloading](http://stackoverflow.com/questions/4421706/operator-overloading) — Cory Kramer, Nov 14 '14 at 17:36

score 2 · Answer 1 · answered Nov 14 '14 at 17:38

2

return ComplexNumber(newValue);

There is no constructor of ComplexNumber which accepts only one argument.

answered Nov 14 '14 at 17:38

Venkatesh

1,529
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score 0 · Answer 2 · answered Nov 14 '14 at 17:39

You don't have any constructor that take one value(double) as a parameter
Add this to your implementation file

ComplexNumber::ComplexNumber(double val)
{
double complexNumberValue = val;
double realNumberValue = 0;
}

This will fix the issue but you have to figure out yourself what to do for the logic part

score 0 · Answer 3 · answered Nov 14 '14 at 17:40

0

You only have a two argument constructor, but you are trying to invoke a single argument constructor.

answered Nov 14 '14 at 17:40

b4hand

9,115
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Arithmetic Operator Overloading C++

3 Answers3