I'm doing this equation
double1 * ((double2/double3) ^ 2.333)
getting error
operator '
^' cannot be used on type double.
what variable should I use instead of double?
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ROMANIA_engineer
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Himarm
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1^ is __not__ Math.Pow but Logical XOR – TaW Nov 10 '14 at 14:38
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an explanation to my ^ , im translating a vb6 program to c# so if ^ is not a correct c# var thats fine too. – Himarm Nov 10 '14 at 14:39
1 Answers
7
Use Math.Pow(value, exponent) instead.
Math.Pow(3,2) outputs 9
The operator you attempted to use (^) cannot be used for this purpose. It is a logical XOR and should be used for bitwise exclusive OR operations.
grovesNL
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1Additional note as to why it doesn't work with what he has: `^` is actually `XOR`. – Rob Nov 10 '14 at 14:39
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math.pow(this would be the value i want to raise, and this would be what i want it raised by?) so math.pow((double2/double3), 2.333) ? – Himarm Nov 10 '14 at 14:42
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@Himarm: Yes, in my example it would be `3` raised to a power of `2`. – grovesNL Nov 10 '14 at 14:43
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@Himarm: Please accept my answer by clicking the checkbox to the left, to let future viewers know that this is the correct solution. – grovesNL Nov 10 '14 at 14:45
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