PHP IF ELSE issue, can not get correct answers

Question

I wrote php function for get weekend, this "$data['projects']" is not empty, but it is redirect to $end = date("Y-m-d", strtotime('next sunday'));

function weekendignSet(){
     if(!empty($data['projects'])){
         $end = $data['projects'][0]->week_end_day;
      }else{
         if(!empty($_GET['week_ending'])){
             $end = $_GET['week_ending'];
         }else{
             $end = date("Y-m-d", strtotime('next sunday'));
         }
      }
      return $end;
}

What is the error? thank you

try to use `if(!isset($data['projects']))` and tell us how it went — Ares Draguna, Oct 28 '14 at 11:23
@AresDraguna `!empty` will automatically check if the value is set. — Fluffeh, Oct 28 '14 at 11:23
@Fluffeh `!isset` will check if the `projects` is actually set... `!empty` just checks if there is a value in `projects` — Ares Draguna, Oct 28 '14 at 11:25
@AresDraguna The first check of `empty` is whether the value is set - then it checks if it is empty. http://stackoverflow.com/a/7191642/1450077 — Fluffeh, Oct 28 '14 at 11:26
@AresDraguna So you're saying that `empty($data['projects'])` returns `false` if `$data['projects']` is not set? — JJJ, Oct 28 '14 at 11:26
@Fluffeh I did not knew that empty checks if its set first... thank you for that link! — Ares Draguna, Oct 28 '14 at 12:20

score 0 · Answer 1 · answered Oct 28 '14 at 11:24

0

You need to pass $data to function then it will check in if() else you always goes in else condition try

function weekendignSet($data){

on calling :-

weekendignSet($data);

answered Oct 28 '14 at 11:24

Rakesh Sharma

13,570
4
35
42

score 0 · Answer 2 · answered Oct 28 '14 at 11:26

0

Your function needs an input paramater named "$data"

answered Oct 28 '14 at 11:26

Thilo Habenreich

94
2

score 0 · Answer 3 · answered Oct 28 '14 at 11:27

Make the $data a global variable, or pass it into a function:

global $data;
$data = array();
function weekendignSet(){
     global $data;
     if(!empty($data['projects'])){
         $end = $data['projects'][0]->week_end_day;
      }else{
         if(!empty($_GET['week_ending'])){
             $end = $_GET['week_ending'];
         }else{
             $end = date("Y-m-d", strtotime('next sunday'));
         }
      }
      return $end;
}

or

$data = array();
function weekendignSet($data){
     if(!empty($data['projects'])){
         $end = $data['projects'][0]->week_end_day;
      }else{
         if(!empty($_GET['week_ending'])){
             $end = $_GET['week_ending'];
         }else{
             $end = date("Y-m-d", strtotime('next sunday'));
         }
      }
      return $end;
}
weekendignSet($data);

PHP IF ELSE issue, can not get correct answers

3 Answers3