how can java return false when comparing 2 numbers which has exactly the same type and value?

Question

<br><% if (overLimit != null) {%><%=overLimitItemNO.getClass().equals(shoppingVO.getItem_no().getClass())%><%}%>
<br><% if (overLimit != null) {%><%=overLimitItemNO.getClass()%> vs <%=shoppingVO.getItem_no().getClass()%><%}%>
<br><% if (overLimit != null) {%><%=overLimitItemNO%> vs <%=shoppingVO.getItem_no()%><%}%> 
<br><% if (overLimit != null) {%><%=overLimitItemNO == shoppingVO.getItem_no()%><%}%>

and it shows the following on the browser

true 

class java.lang.Integer vs class java.lang.Integer 

300008 vs 300008 

false

When using an `Integer`, you **need** to use the `.equals` method. — Pokechu22, Oct 17 '14 at 19:45

score 2 · Answer 1 · answered Oct 17 '14 at 19:45

2

You need to use obj1.equals(obj2). == on objects only compares whether the two are the same exact instance

answered Oct 17 '14 at 19:45

ControlAltDel

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score 0 · Answer 2 · answered Oct 17 '14 at 19:45

0

Use .equals when comparing Integer's otherwise you are comparing object refs.

answered Oct 17 '14 at 19:45

stevebot

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how can java return false when comparing 2 numbers which has exactly the same type and value?

2 Answers2