Regex difficulty

Question

The first preg_match is line 32. I imagine the second preg_match is going to give the same error. How do I fix this? Thanks.

Warning: preg_match(): No ending delimiter '^' found in 
C:\xampp\htdocs\(...)\index.php on line 32



if (preg_match('^(?=.{4,20}$)(?![_.])(?!.*[_.]{2})[a-zA-Z0-9._]+(?<![_.])$', 
$userCreation)) {
    if(preg_match('^([1-zA-Z0-1@.\s]{4,30})$', $passwordCreation)) {

Question title writing difficulty? – mario Oct 17 '14 at 01:10 — mario, Oct 17 '14 at 01:10

score 1 · Accepted Answer · answered Oct 17 '14 at 00:52

1

Use delimiters (/) at the beginning and end of regexes:

if (preg_match('/^(?=.{4,20}$)(?![_.])(?!.*[_.]{2})[a-zA-Z0-9._]+(?<![_.])$/', 
$userCreation)) {
    if(preg_match('/^([1-zA-Z0-1@.\s]{4,30})$/', $passwordCreation)) {

answered Oct 17 '14 at 00:52

Gergo Erdosi

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It is good to mention that they do not have to be `/` - it can be any symbol. Like the one he has - regexp starts with `^` and expects `^` at the end. – Cheery Oct 17 '14 at 00:54
@Cheery Yes, thanks for the note. – Gergo Erdosi Oct 17 '14 at 00:58

Regex difficulty

1 Answers1