Unable to scan char variable after scanning int in C

Question

I am having problem scanning char variable , my code is

#include <stdio.h>
#include <conio.h>

void main() 
{
clrscr();
int a;
float b;
char c;

printf("Enter value for int variable \n");
scanf("%d",&a);

printf("Enter value for float variable \n");
scanf("%f",&b);

printf("Enter value for char variable \n");
scanf("%c",&c); //scanning is automatically skipped !!! 

getch();
}

Please tell me , why is this happening and what can i do to solve it !

I would add `'\n'` at the end of every string passed to `scanf`. — barak manos, Oct 16 '14 at 15:14

score 1 · Accepted Answer · answered Oct 16 '14 at 15:09

because of the stored enter key press [considered as character input]. use one getch(); before the third scanf().

alternatively, use (scanf(" %c",&c);) [mind the space before %c] which will get rid of any number of whitespace [buffered] character present before actual input.

Unable to scan char variable after scanning int in C

1 Answers1