Existence of Parentheses after the new, make any different in C++11

Question

Look at the tow declarations bellow. These two method make any different in C++ 11? I checked the story about C++03 here

Class A{int m;}

1. A* a = new A
2. A* a = new A();

Answer 1

It's the same in C++11 as it was in C++03.

The first is default-initialision, leaving m uninitialised.

The second is value-initialisation, initialising m to zero.

If the class had a user-provided default constructor, then both would do the same thing, calling that constructor.