how do i get rid of extra array in python?

Question

so my code is as follows:

  promotion = [[""], ["promotion applied"],[""]]

how do I make it go from there to this state:

 promotion = ["", "promotion applied", ""]

falsetru · Accepted Answer · 2014-09-24T15:11:20.743

1

>>> promotion = [[""], ["promotion applied"],[""]]
>>> [x[0] for x in promotion]
['', 'promotion applied', '']

with tuple unpacking:

>>> [x for x, in promotion]  # works only if all items are single-item sequences.
['', 'promotion applied', '']

edited Sep 24 '14 at 15:11

answered Sep 24 '14 at 15:09

falsetru

whoops, I was that editor-in-error. Just noticed :) – Adam Smith Sep 24 '14 at 15:10
1

@AdamSmith, No problem. rolled back :) – falsetru Sep 24 '14 at 15:11
what about the promotion is = to [[""], ["","promotion applied", "", "value", ""], [""]] and I want it to be ["", "promotion applied",""] – slopeofhope Sep 24 '14 at 15:15
@slopeofhope, So you want to get the first non-empty string, but empty-string if there are only empty strings? – falsetru Sep 24 '14 at 15:17
it doesn't have to be the first non-empty string..any value i specify in this promotion applied – slopeofhope Sep 24 '14 at 15:19
@slopeofhope, I don't understand `any value i specify in this promotion applied`. – falsetru Sep 24 '14 at 15:19
@slopeofhope, Anyway, here's code that will return the first non-empty strings: http://ideone.com/DoiqzF – falsetru Sep 24 '14 at 15:21

1 Answers1