Remove month and day from date string

Question

I'm trying to figure out how I can remove the Day and Month from this variable as it's looped. I've tried several strtotime() functions but I can't get the syntax quite right.

foreach ( $results as $result) {
   echo $result->date . "<br />";
}

Shows dates like this:

2014-09-03
2013-09-09
2011-06-01

How can I reassign the variable $result->date so that it only shows the Year like this:

2014
2013
2011

zavg · Accepted Answer · 2014-09-18T19:45:59.957

1

Easy way is just to explode date string using '-' delimiter and take year element:

foreach ( $results as $result) {
   $dateArr = explode('-', $result->date);
   echo $dateArr[0] . "<br />";
}

More complicated way is to convert sting to UNIX timestamp using strtotime function and then reformat it with date function.

edited Sep 18 '14 at 19:45

answered Sep 18 '14 at 19:40

zavg

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Hi thanks, this just gives me dashes for the years, my output is: - - - – BradM Sep 18 '14 at 19:48
Sorry, look at corrected answer – zavg Sep 18 '14 at 19:49
That's Perfect!! Thanks a lot! – BradM Sep 18 '14 at 19:51
@BradM I had forgotten the order of arguments in explode function :) You are welcome. – zavg Sep 18 '14 at 19:51

score 1 · Answer 2 · answered Sep 18 '14 at 19:41

1

Just use substr:

$date = '2014-09-18';
echo substr($date, 0, 4);   // Outputs 2014

answered Sep 18 '14 at 19:41

Phil Cross

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score 0 · Answer 3 · answered Sep 18 '14 at 19:42

0

this can solve your problem

foreach ( $results as $result) {
   $dateParams = explode("-",$result->data);
   $result->date = $dateParams[0];
   echo $result->date."<br />";
}

answered Sep 18 '14 at 19:42

ReZa

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Remove month and day from date string

3 Answers3