How to delete by regexp in Java?

Question

Now I have this:

    String s = "1<script type='text/javascript'>2</script>3<script type='text/javascript'>3</script>5";
    Pattern pattern = Pattern.compile("<script.*</script>");
    Matcher matcher = pattern.matcher(s);

    while (matcher.find()) {
        s = s.replace(matcher.group(), "");
    }

    System.out.println(s);

The result is

15

But I need

135

In PHP we have /U modificator, but what should I do in Java? I thought about sth like this, but it is incorrect:

Pattern pattern = Pattern.compile("<script[^(script)]*</script>");

@fildor, this is my test task for the job: to write a web scraper, and can't use 3rd party libraries =( — sinedsem, Sep 10 '14 at 09:39

vks · Accepted Answer · 2014-09-10T10:07:07.783

3

<script([^>]*)?>.*?<\/script>

Try this.You needed a ? for lazy match or shorter match.

See demo.

http://regex101.com/r/kO7lO2/3

edited Sep 10 '14 at 10:07

answered Sep 10 '14 at 09:34

vks

65,133
10
87
119

This doesn't catch ``, as the title of the question suggests. – stuXnet Sep 10 '14 at 09:50
@stuXnet – vks Sep 10 '14 at 10:06

score 1 · Answer 2 · answered Sep 10 '14 at 09:37

1

replaceAll the below regex by empty string:

<script [^>]*>[^<]*</script>

answered Sep 10 '14 at 09:37

Kent

181,427
30
222
283

Would this replace ``? – stuXnet Sep 10 '14 at 09:43
@stuXnet what was your test result? note there is a space after the ` – Kent Sep 10 '14 at 09:55

How to delete .. by regexp in Java?

2 Answers2

How to delete by regexp in Java?