Casting float to string without scientific notation

Question

The float:

fl = 0.000005

casts to String as str(fl)=='5e-06'. however, I want it to cast as str(fl)='0.000005' for exporting to CSV purposes.

How do I achieve this?

Do you need to use `str()` or can you do something like `'{:f}'.format(fl)`? — grc, Sep 04 '14 at 12:30
@PadraicCunningham @grc I get exception `Traceback (most recent call last): File "", line 1, in ValueError: zero length field name in format ` — user2763361, Sep 04 '14 at 12:32

score 1 · Answer 1 · answered Sep 04 '14 at 12:34

1

You can just use the standard string formatting option stating the precision you want

>>> fl = 0.000005
>>> print '%.6f' % fl
0.000005

answered Sep 04 '14 at 12:34

flakes

What if I just want it to the exact accuracy as I specified `fl` with. So if I set `fl = 0.00214`, I want `string = '0.00214'`, or if I set `fl = 0.0000000006`, I want `string = '0.0000000006'`. – user2763361 Sep 04 '14 at 12:36

Michel Keijzers · Answer 2 · 2021-01-17T21:15:34.267

1

Use

fl = 0.00005
s = '%8.5f' % fl
print s, type(s)

Gives

0.00005 <type 'str'>

In case you want no extra digits, use %g (although it uses exponential notation for e.g. 0.000005). See for example:

fl = 0.0005
s = '%g' % fl
print s, type(s)

fl = 0.005
s = '%g' % fl
print s, type(s)

Gives

0.0005 <type 'str'>
0.005 <type 'str'>

edited Jan 17 '21 at 21:15

answered Sep 04 '14 at 12:36

Michel Keijzers

2

`%g` will give scientific notation for numbers like 0.000005. BTW your `str` calls are not needed. – interjay Sep 04 '14 at 12:42
@interjay thanks for the comment, I updated my answer accordingly. – Michel Keijzers Jan 17 '21 at 21:15

2 Answers2